堆排序的python实现

import math

def build_heap(arr):
    # 创建堆
    for i in range(1, len(arr)):
        s = i
        p = math.ceil(s / 2) - 1
        while p >= 0:
            if arr[s] > arr[p]:
                arr[s], arr[p] = arr[p], arr[s]
            else:
                break
            s = p
            p = math.ceil(s / 2) - 1
    return arr

def sort(arr):
    # 创建排序列表
    result_list = []
    while arr:
        arr = build_heap(arr)
        result_list.append(arr.pop(0))
    return result_list

l = [5, 2, 7, 8, 6, 1, 4, 9, 10, 1, 2, 3, 4, 100]
print(sort(l))

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